Merge pull request 'main' (#3) from main into JD_Branch

Reviewed-on: #3

highscores.txt

@@ -1,4 +1,5 @@
 Player1;19887
+Player1;19843
 Lena;19811
 Lena;19702
 Player1;19578
@@ -7,4 +8,3 @@ Lena;9980
 Lena;9978
 Lena;9978
 Lena;9976
-Lena;9975

stack.c

@@ -4,12 +4,12 @@
 // Push Daten auf den Stack legen.
 StackNode *push(StackNode *stack, void *data)
 {
-    StackNode *node = (StackNode *)malloc(sizeof(StackNode));
+    StackNode *node = malloc(sizeof(StackNode));
     if(node == NULL)
         return stack; // allocation failed -> return unchanged stack
 
-    node->data = data;      // Set the data for the new node   
+    node->data = data;      // Setze Daten   
-    node->next = stack;     // New node points to the previous top of the stack
+    node->next = stack;     // Setze nächsten Knoten auf aktuellen Stack
     return node;
 }
 
@@ -21,7 +21,7 @@ StackNode *pop(StackNode *stack)
         return NULL;
 
     StackNode *next = stack->next;
-    // Do NOT free stack->data here; caller owns the pointed data
+    // Speicher des aktuellen Knotens freigeben
     free(stack);
     return next;
 }

test_stack.c

@@ -8,37 +8,45 @@ int main(void)
     StackNode *s = NULL;
 
     // push 3 integers
-    int *a = malloc(sizeof(int)); *a = 1; s = push(s, a);
+    int *a = malloc(sizeof(int)); 
-    int *b = malloc(sizeof(int)); *b = 2; s = push(s, b);
+    *a = 1; 
-    int *c = malloc(sizeof(int)); *c = 3; s = push(s, c);
+    s = push(s, a);
+    int *b = malloc(sizeof(int)); 
+    *b = 2; 
+    s = push(s, b);
+    int *c = malloc(sizeof(int)); 
+    *c = 3; 
+    s = push(s, c);
 
-    // top should be c (3)
+    // oben liegt c (3)
     int *topv = (int *)top(s);
     if(topv == NULL || *topv != 3) { fprintf(stderr, "stack top expected 3\n"); return 1; }
 
-    // pop -> now top should be 2
+    // oben liegt nun 2
     s = pop(s);
     topv = (int *)top(s);
     if(topv == NULL || *topv != 2) { fprintf(stderr, "stack top expected 2 after pop\n"); return 2; }
 
-    // pop -> now top should be 1
+    // oben liegt nun 1
     s = pop(s);
     topv = (int *)top(s);
     if(topv == NULL || *topv != 1) { fprintf(stderr, "stack top expected 1 after pop\n"); return 3; }
 
-    // pop last
+    // letzen Stapelinhalt holen
     s = pop(s);
     if(s != NULL) { fprintf(stderr, "stack expected empty after popping all\n"); return 4; }
 
-    // free stored data (stack does not free data)
+    // Eigenen Speicher freigeben
-    free(a); free(b); free(c);
+    free(a); 
+    free(b); 
+    free(c);
 
-    // test clearStack on empty and small stacks
+    // test clearStack mit leerem Stack
     s = push(s, malloc(sizeof(int)));
     s = push(s, malloc(sizeof(int)));
     clearStack(s); // clearStack must free nodes but not payload; free payloads not necessary because we leaked intentionally for test of API
     // Note: above payloads are not freed (stack API spec); this test ensures clearStack doesn't crash.
-    // Success
+    // Funktioniert alles
     printf("test_stack: OK\n");
     return 0;
 }