generated from freudenreichan/info2Praktikum-DobleSpiel
105 lines
3.1 KiB
C
105 lines
3.1 KiB
C
#include <string.h>
|
|
#include "stack.h"
|
|
#include "bintree.h"
|
|
|
|
//TODO: binären Suchbaum implementieren
|
|
/* * `addToTree`: fügt ein neues Element in den Baum ein (rekursiv),
|
|
* `clearTree`: gibt den gesamten Baum frei (rekursiv),
|
|
* `treeSize`: zählt die Knoten im Baum (rekursiv),
|
|
* `nextTreeData`: Traversierung mit Hilfe des zuvor implementierten Stacks. */
|
|
|
|
// Adds a copy of data's pointer destination to the tree using compareFct for ordering. Accepts duplicates
|
|
// if isDuplicate is NULL, otherwise ignores duplicates and sets isDuplicate to 1 (or to 0 if a new entry is added).
|
|
TreeNode *addToTree(TreeNode *root, const void *data, size_t dataSize, CompareFctType compareFct, int *isDuplicate)
|
|
{
|
|
if(data!= NULL && dataSize > 0)
|
|
{
|
|
if(root == NULL) //Abbruchbedingung: Keine Wurzel vorhanden, deshalb fügen wir hier einen neuen Knote ein
|
|
{
|
|
TreeNode *newNode = (TreeNode *)malloc(sizeof(TreeNode));
|
|
if(newNode == NULL)
|
|
{
|
|
return NULL;
|
|
}
|
|
newNode->data = malloc(dataSize);
|
|
if(newNode->data == NULL)
|
|
{
|
|
free(newNode);
|
|
return NULL;
|
|
}
|
|
memcpy(newNode->data, data, dataSize);
|
|
newNode->left = NULL;
|
|
newNode->right = NULL;
|
|
|
|
if(isDuplicate!= NULL)
|
|
{
|
|
*isDuplicate = 0;
|
|
}
|
|
|
|
return newNode;
|
|
}
|
|
int cmp = compareFct(root->data, data);
|
|
if(cmp > 0)
|
|
{
|
|
root->left = addToTree(root->left, data, dataSize, compareFct, isDuplicate);
|
|
}
|
|
else if(cmp < 0){
|
|
root->right = addToTree(root->right, data, dataSize, compareFct, isDuplicate);
|
|
}
|
|
else
|
|
{
|
|
if (isDuplicate) {
|
|
*isDuplicate = 1;
|
|
}
|
|
else {
|
|
// isDuplicate == NULL → trotzdem ein Duplikat einfügen (z.B. rechts)
|
|
root->right = addToTree(root->right, data, dataSize, compareFct, NULL);
|
|
}
|
|
}
|
|
return root;
|
|
}
|
|
return NULL;
|
|
}
|
|
|
|
// Iterates over the tree given by root. Follows the usage of strtok. If tree is NULL, the next entry of the last tree given is returned in ordering direction.
|
|
// Use your implementation of a stack to organize the iterator. Push the root node and all left nodes first. On returning the next element,
|
|
// push the top node and push all its left nodes.
|
|
void *nextTreeData(TreeNode *root)
|
|
{
|
|
if(root == NULL)
|
|
{
|
|
|
|
|
|
}
|
|
stackNode.top(root);
|
|
}
|
|
|
|
// Releases all memory resources (including data copies).
|
|
void clearTree(TreeNode *root)
|
|
{
|
|
if (root == NULL)
|
|
{
|
|
return;
|
|
}
|
|
// Erst linken Knoten löschen
|
|
clearTree(root->left);
|
|
|
|
// Dann rechten Knoten löschen
|
|
clearTree(root->right);
|
|
|
|
// Dann eigenen Speicher freigeben
|
|
free(root->data);
|
|
free(root);
|
|
}
|
|
|
|
|
|
// Returns the number of entries in the tree given by root.
|
|
unsigned int treeSize(const TreeNode *root)
|
|
{
|
|
if(root == NULL)
|
|
{
|
|
return numNodes;
|
|
}
|
|
return 1 + treeSize(root->left) + treeSize(root->right); //1, weil eine Wurzel gefunden wurde und dann immer plus eins fuer einen Teilbaum
|
|
|
|
} |