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- \section{Dualitätskonstante verlustbehaftete Bauelemente}
- \begin{align*}
- \begin{tikzpicture}[scale=2]
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=.5cm]%Kondensator -
- \draw (0,0)--(.475,0) (.475,-.125)--(.475,.125) (.525,-.125)--(.525,.125) (.525,0)--(1,0)node at (.5,.133) [above] {$C$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=0cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$G$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=.5cm,yshift=-.5cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1.5cm,yshift=-.5cm]%Spule -
- \draw (0,0)--(.3,0) (.7,0)--(1,0)node at (.5,.0667) [above] {$L$};
- \fill (.3,-0.0667)rectangle(.7,0.0667);
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]
- \draw (0,0)--(1,0) (1.1,.5)--(1,.5)--(1,0) (.6,-.5)--(.5,-.5)--(.5,0) (1.9,.5)--(2,.5)--(2,0)(2.4,-.5)--(2.5,-.5)--(2.5,0) (2,0)--(3,0);
- \fill(.5,0)circle(.03) (1,0)circle(.03)(2,0)circle(.03) (2.5,0)circle(.03);
- \fill(0,0)circle(.05)node[left]{$a$};
- \fill(3,0)circle(.05)node[right]{$b$};
- \end{scope}
- \end{tikzpicture}
- \end{align*}
- $\hspace{3cm} R=20\,\ohm\quad L=1\,\milli\henry\quad C=100\,\nano\,\farad\quad G=2\,\milli\siemens$\\
- \renewcommand{\labelenumi}{\alph{enumi})}
- \begin{enumerate}
- \item Geben Sie das duale Schaltbild für den Zweipol $a-b$ an und berechnen Sie dessen Elemente für $R^2_D=(100\,\ohm)^2$.
- \item Welches verlustbehaftete Bauelement stellt die Reihenschaltung $R$ und $L$ dar?
- \item Welches verlustbehaftete Bauelement stellt die Parallelschaltung $G$ und $C$ dar?
- \item Interpretieren Sie das Ergebnis der Bauelementegrößen der beiden dualen Schaltungen in Bezug auf verlustbehaftete Bauelemente.
- \end{enumerate}
- \ifthenelse{\equal{\toPrint}{Lösung}}{%
- \begin{align}
- \intertext{Formeln:}
- %\uline{Z}_1(\omega)&=R^2_D \cdot \uline{Y}_2(\omega)
- R\cdot R_{dual}&=R^2_D \quad = \quad\text{Dualitätskonstante}\\
- R^2_D&=\frac{L}{C}=\frac{L_{dual}}{C}=\frac{L}{C_{dual}}
- \end{align}
- Berechnung:\\[\baselineskip]
- Duales Netzwerk:\\
- Parallel $\Leftrightarrow$ Serie\\
- Leitwert $\Leftrightarrow$ Widerstand\\
- Kapazität $\Leftrightarrow$ Induktivität\\
- \begin{align*}
- \begin{tikzpicture}[scale=2]
- \begin{scope}[>=latex,very thick,xshift=2cm,yshift=.25cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$G_R$};
- \draw node at (.75,.35) [above] {\footnotesize{Verlustbehafteter Kondensator}};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=2cm,yshift=-.25cm]%Kondensator -
- \draw (0,0)--(.475,0) (.475,-.125)--(.475,.125) (.525,-.125)--(.525,.125) (.525,0)--(1,0)node at (.5,.133) [above] {$C_L$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_G$};
- \draw node at (.75,-.5) [above] {\footnotesize{Verlustbehaftete Spule}};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=0cm]%Spule -
- \draw (0,0)--(.3,0) (.7,0)--(1,0)node at (.5,.0667) [above] {$L_C$};
- \fill (.3,-0.0667)rectangle(.7,0.0667);
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]
- \draw (2.1,.25)--(2,.25)--(2,-.25)--(2.1,-.25) (2.9,.25)--(3,.25)--(3,-.25)--(2.9,-.25) (3,0)--(4,0);
- \fill(2,0)circle(.03)(3,0)circle(.03);
- \fill(0,0)circle(.05)node[left]{$a$};
- \fill(4,0)circle(.05)node[right]{$b$};
- \end{scope}
- \end{tikzpicture}
- \end{align*}
- \begin{align*}
- \intertext{a) Duale Bauelemente:}
- R_G&=\frac{R^2_D}{R}=R^2_D\cdot G=(100\,\ohm)^2\cdot 2\,\milli\siemens=\uuline{20\,\ohm}\quad(=R\text{ !})\\
- L_C&=C\cdot R^2_D=100\cdot \power{10}{-9}\frac{\,\ampere\second}{\volt}\cdot (100\frac{\,\volt}{\ampere})^2=\uuline{1\,\milli\henry}=\quad(=L\text{ !})\\
- G_R&=\frac{R}{R^2_D}=\frac{20\,\ohm}{(100\,\ohm)^2}=\uuline{2\,\milli\siemens} \quad(=G\text{ !)}\\
- C_L&=\frac{L}{R^2_D}=\frac{1\,\milli\henry}{(100\,\ohm)^2}=\uuline{100\,\nano\farad} \quad(=C\text{ !)}\\
- \intertext{b) Verlustbehaftete Spule.}
- \intertext{c) Verlustbehafteter Kondensator.}
- \intertext{d) Die duale Schaltung ist die Reihenschaltung der gleichen verlustbehafteten Bauteile Spule und Kondensator.}
- \end{align*}
- \clearpage
- }{}%
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