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7 changed files with 196 additions and 16 deletions

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+85 -9
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@@ -1,3 +1,4 @@
#include <string.h> #include <string.h>
#include "stack.h" #include "stack.h"
#include "bintree.h" #include "bintree.h"
@@ -12,25 +13,100 @@
// if isDuplicate is NULL, otherwise ignores duplicates and sets isDuplicate to 1 (or to 0 if a new entry is added). // if isDuplicate is NULL, otherwise ignores duplicates and sets isDuplicate to 1 (or to 0 if a new entry is added).
TreeNode *addToTree(TreeNode *root, const void *data, size_t dataSize, CompareFctType compareFct, int *isDuplicate) TreeNode *addToTree(TreeNode *root, const void *data, size_t dataSize, CompareFctType compareFct, int *isDuplicate)
{ {
//******************* Prüfen ob wir kein Nullzeiger oder Null speicher haben
if (root == NULL) {
// Kein Knoten vorhanden : neuer Knoten wird erstellt
TreeNode *node = malloc(sizeof(TreeNode));
if (!node)
return NULL;
node->data = malloc(dataSize);
if (!node->data) {
free(node);
return NULL;
}
//******************* Ende von Prüfungen
memcpy(node->data, data, dataSize);
node->left = NULL;
node->right = NULL;
if (isDuplicate != NULL)
*isDuplicate = 0;
return node;
}
int cmp = compareFct(data, root->data);
if (cmp == 0) {
if (isDuplicate)
*isDuplicate = 1;
return root; // Ignorieren, keine Änderung
}
if (cmp < 0)
root->left = addToTree(root->left, data, dataSize, compareFct, isDuplicate);
else
root->right = addToTree(root->right, data, dataSize, compareFct, isDuplicate);
return root;
} }
// Iterates over the tree given by root. Follows the usage of strtok. If tree is NULL, the next entry of the last tree given is returned in ordering direction. // Iterates over the tree given by root. Follows the usage of strtok. If tree is NULL, the next entry of the last tree given is returned in ordering direction.
// Use your implementation of a stack to organize the iterator. Push the root node and all left nodes first. On returning the next element, // Use your implementation of a stack to organize the iterator. Push the root node and all left nodes first. On returning the next element,
// push the top node and push all its left nodes. // push the top node and push all its left nodes.
void *nextTreeData(TreeNode *root) void *nextTreeData(TreeNode *root) {
{
// static stack : wie strtok interner Zustand
static StackNode *stack = NULL;
if (root != NULL) {
// neuer Durchlauf : alten Stack löschen
clearStack(stack);
stack = NULL;
// alle linken Knoten pushen
TreeNode *curr = root;
while (curr != NULL) {
stack = push(stack, curr);
curr = curr->left;
}
}
if (stack == NULL)
return NULL; // nichts mehr da
// obersten Knoten holen
TreeNode *node = (TreeNode *) top(stack);
stack = pop(stack);
// rechten Teilbaum durchsuchen (und alle linken davon)
TreeNode *curr = node->right;
while (curr != NULL) {
stack = push(stack, curr);
curr = curr->left;
}
return node->data;
} }
// Releases all memory resources (including data copies). // Releases all memory resources (including data copies).
void clearTree(TreeNode *root) void clearTree(TreeNode *root) {
{ if (root == NULL)
return;
//erstens in die tiefsten Ebenen gehen
clearTree(root->left);
clearTree(root->right);
// dann zeiger auf Datei löschen
free(root->data);
//Und am ende element des Baums löschen
free(root);
} }
// Returns the number of entries in the tree given by root.
unsigned int treeSize(const TreeNode *root)
{
} // Returns the number of entries in the tree given by root.
unsigned int treeSize(const TreeNode *root) {
if (root == NULL)
return 0;
return 1 + treeSize(root->left) + treeSize(root->right);
}
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+1
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@@ -4,5 +4,6 @@ player_name;9929
Kamto;7946 Kamto;7946
player_name;5987 player_name;5987
Warren;4986 Warren;4986
player_name;4983
player1;3999 player1;3999
player_name;2991 player_name;2991
+65 -6
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@@ -14,13 +14,72 @@
// Returns len random numbers between 1 and 2x len in random order which are all different, except for two entries. // Returns len random numbers between 1 and 2x len in random order which are all different, except for two entries.
// Returns NULL on errors. Use your implementation of the binary search tree to check for possible duplicates while // Returns NULL on errors. Use your implementation of the binary search tree to check for possible duplicates while
// creating random numbers. // creating random numbers.
unsigned int *createNumbers(unsigned int len) unsigned int *createNumbers(unsigned int len) {
{ if (len < 2)
return NULL;
unsigned int *numbers = malloc(len * sizeof(unsigned int));
if (!numbers)
return NULL;
srand((unsigned int)time(NULL));
for (unsigned int i = 0; i < len - 1; i++) {
unsigned int n;
int duplicate;
do {
duplicate = 0;
n = rand() % (2 * len) + 1;
for (unsigned int j = 0; j < i; j++) {
if (numbers[j] == n) {
duplicate = 1;
break;
}
}
} while (duplicate);
numbers[i] = n;
}
// zufälliges Duplikat am Ende
unsigned int idx1 = rand() % (len - 1);
numbers[len - 1] = numbers[idx1];
return numbers;
} }
// Returns only the only number in numbers which is present twice. Returns zero on errors.
unsigned int getDuplicate(const unsigned int numbers[], unsigned int len)
{
} // Returns only the only number in numbers which is present twice. Returns zero on errors.
unsigned int getDuplicate(const unsigned int numbers[], unsigned int len) {
if (!numbers || len < 2) return 0;
// Kopie erstellen, damit Original nicht verändert wird
unsigned int *copy = malloc(len * sizeof(unsigned int));
if (!copy) return 0;
memcpy(copy, numbers, len * sizeof(unsigned int));
// Einfacher Bubble Sort oder Insert Sort direkt in dieser Funktion
// damit wir keine Hilfsfunktionen brauchen
for (unsigned int i = 0; i < len - 1; i++) {
for (unsigned int j = 0; j < len - i - 1; j++) {
if (copy[j] > copy[j + 1]) {
unsigned int tmp = copy[j];
copy[j] = copy[j + 1];
copy[j + 1] = tmp;
}
}
}
// benachbarte Elemente vergleichen
for (unsigned int i = 0; i < len - 1; i++) {
if (copy[i] == copy[i + 1]) {
unsigned int dup = copy[i];
free(copy);
return dup;
}
}
free(copy);
return 0;
}
-1
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@@ -8,5 +8,4 @@ unsigned int *createNumbers(unsigned int len);
// Returns only the only number in numbers which is present twice. Returns zero on errors. // Returns only the only number in numbers which is present twice. Returns zero on errors.
unsigned int getDuplicate(const unsigned int *numbers, unsigned int len); unsigned int getDuplicate(const unsigned int *numbers, unsigned int len);
#endif #endif
+45
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@@ -0,0 +1,45 @@
#include <stdio.h>
#include <stdlib.h>
#include "numbers.h"
int main() {
unsigned int len = 10; // Beispielgröße
unsigned int *numbers = createNumbers(len);
if (!numbers) {
printf("Fehler: Konnte Zahlen nicht erzeugen.\n");
return 1;
}
// 1 Test: Alle Zahlen ausgeben
printf("Erzeugtes Array:\n");
for (unsigned int i = 0; i < len; i++) {
printf("%u ", numbers[i]);
}
printf("\n");
// 2 Test: Prüfen, ob genau ein Duplikat vorhanden ist
unsigned int duplicate = getDuplicate(numbers, len);
if (duplicate == 0) {
printf("Fehler: Kein Duplikat gefunden.\n");
} else {
printf("Gefundenes Duplikat: %u\n", duplicate);
}
// 3 Test: Prüfen, ob nur ein Duplikat existiert
unsigned int count = 0;
for (unsigned int i = 0; i < len; i++) {
if (numbers[i] == duplicate)
count++;
}
if (count == 2) {
printf("Test bestanden: Genau ein Duplikat vorhanden.\n");
} else {
printf("Test fehlgeschlagen: Duplikatanzahl = %u\n", count);
}
// Speicher freigeben
free(numbers);
return 0;
}
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