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- \section{Spannung Vierpol}
- %\renewcommand{\theequation}{0}
- Berechnung Sie $\uline{U}_0$
- \begin{align*}
- \begin{tikzpicture}[scale=2]
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=1cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_1$};
- \draw [->,red] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{I}_1$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=2cm,yshift=2cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_2$};
- \draw [->,blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{U}_R=R_2\cdot \uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick, xshift=1.5cm, yshift=0cm]% Vierpol
- \draw (0,-.2)rectangle(2.0,1.2)node at(.75,.5)[right]{$(\uline{Z})$};
- \draw (0,0)--(-.5,0)(0,1)--(-.5,1)(2,0)--(2.5,0)(2,1)--(2.5,1);
- \end{scope}
- \begin{scope}[>=latex,very thick, xshift=0, yshift=0]
- \draw (0,0)--(1,0);
- \draw (1,1)--(1,2)--(2,2) (3,2)--(4,2)--(4,1);
- \draw (1,0)--(1,-.5)--(4,-.5)--(4,0);
- \fill (0,0)circle(.05) (0,1)circle(.05) (1,0)circle(.05) (1,1)circle(.05) (4,0)circle(.05) (4,1)circle(.05);
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=.75cm,yshift=1cm]% Strompfeil
- \draw [->,red] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=3.25cm,yshift=1cm]% Strompfeil
- \draw [<-,red] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[below]{\footnotesize$\uline{U}_1$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[below]{\footnotesize$\uline{U}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=4cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[below]{\footnotesize$\uline{U}_2$};
- \end{scope}
- \end{tikzpicture}
- \end{align*}
- \begin{align*}
- R_1&=300\,\ohm\\
- R_2&=600\,\ohm\\
- \uline{Z}_{11}&=100\,\kilo\ohm\text{ reell}\\
- \uline{Z}_{21}&=-2\,\mega\ohm\text{ reell}\\
- \uline{U}_1&=1{,}5\,\volt
- %\end{align*}
- %\begin{align*}
- \intertext{Die $\uline{Z}$-Matrix des Vierpols ist gegeben:}
- \begin{bmatrix}
- \uline{U}_0\\
- \uline{U}_2
- \end{bmatrix}
- &=
- \begin{bmatrix}
- \uline{Z}_{11}&0\\
- \uline{Z}_{21}&0
- \end{bmatrix}
- \cdot
- \begin{bmatrix}
- \uline{I}_0\\
- \uline{I}_2
- \end{bmatrix}
- \end{align*}
- \ifthenelse{\equal{\toPrint}{Lösung}}{%
- %\begin{align}
- %\intertext{Formeln:}
- %\end{align}
- Berechnung:
- \begin{align*}
- \begin{tikzpicture}[scale=2]
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=1cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_1$};
- \draw [->,blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$R_1\cdot (\uline{I}_2+\uline{I}_0)$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=2cm,yshift=2cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_2$};
- \draw [->,blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$R_2\cdot \uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick, xshift=0, yshift=0]
- \draw (0,0)--(1,0);
- \draw (1,1)--(1,2)--(2,2) (3,2)--(4,2)--(4,1);
- \draw (1,0)--(1,-.5)--(4,-.5)--(4,0);
- \fill (0,0)circle(.05) (0,1)circle(.05) (1,0)circle(.05) (1,1)circle(.05) (4,0)circle(.05) (4,1)circle(.05);
- \end{scope}
- \begin{scope}[>=latex,very thick, xshift=0, yshift=0]
- \draw (0,0)--(1,0);
- \draw (1,1)--(1,2)--(2,2) (3,2)--(4,2)--(4,1);
- \draw (1,0)--(1,-.5)--(4,-.5)--(4,0)(1,1)--(1.25,1)(4,1)--(3.75,1);
- \fill (0,0)circle(.05) (0,1)circle(.05) (1,0)circle(.05) (1,1)circle(.05) (4,0)circle(.05) (4,1)circle(.05);
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=1.2cm]% Strompfeil
- \draw [->,red] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=3cm,yshift=1.2cm]% Strompfeil
- \draw [<-,red] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$\uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=-.2cm,yshift=1cm]% Strompfeil
- \draw [->,red] (0,0)--(.2,0)node at(.1,0)[above]{\footnotesize$\uline{I}_1$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(-.2,.5)[left]{\footnotesize$\uline{U}_1$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[right]{\footnotesize$\uline{U}_0=\uline{Z}_{11}\cdot \uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=4cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[right]{\footnotesize$\uline{U}_2=\uline{Z}_{21}\cdot \uline{I}_0$};
- \end{scope}
- \end{tikzpicture}
- \end{align*}
- Aus $\uline{Z}$-Matrix folgt:
- \begin{align*}
- \uline{U}_0&=\uline{Z}_{11}\cdot \uline{I}_0 \tag{1}\\
- \uline{U}_2&=\uline{Z}_{21}\cdot \uline{I}_0 \tag{2}
- \intertext{Knoten 1:}
- \uline{I}_1-\uline{I}_2-\uline{I}_0&=0 \tag{3}
- \intertext{Masche 1:}
- \uline{U}_1&=R_1\cdot \uline{I}_1+ \uline{U}_0\tag{4}
- \intertext{Masche 2:}
- \uline{U}_0&=R_2\cdot \uline{I}_2+\uline{U}_2 \tag{5}
- \intertext{Zwei Gleichungen für zwei unbekante Ströme $\uline{I}_0$ und $\uline{I}_2$:}
- \uline{Z}_{11}\cdot \uline{I}_0&=R_2\cdot \uline{I}_2+\uline{Z}_{21}\cdot \uline{I}_0 \tag{1\&2 in 5}\\
- \Rightarrow \uline{I}_2&=\frac{1}{R_2}\cdot (\uline{Z}_{11}-\uline{Z}_{21})\cdot \uline{I}_0 \tag{6}\\
- \uline{U}_1&=\uline{I}_0 \cdot\uline{Z}_{11}+R_1(\uline{I}_0 +\uline{I}_2 ) \tag{7 1\&3 in 4}\\
- \uline{U}_1&=\uline{I}_0\cdot \uline{Z}_{11}+R_1\cdot \uline{I}_0+R_1\cdot \frac{1}{R_2}\cdot (\uline{Z}_{11}-\uline{Z}_{21})\cdot \uline{I}_0 \tag{6 in 7}\\
- &=\left[\uline{Z}_{11}+R_1+\frac{R_1}{R_2}\cdot(\uline{Z}_{11}-\uline{Z}_{21})\right]\cdot \uline{I}_0\\
- &=\left[100\,\kilo\ohm+300\,\ohm+\frac{300\,\ohm}{600\,\ohm}\cdot \Big(100\,\kilo\ohm-(-2\,\mega\ohm)\Big)\right]\cdot \uline{I}_0\\
- &=0{,}103+0{,}5\cdot (100+2000)\,\kilo\ohm \cdot \uline{I}_0=1{,}15\,\mega\ohm\cdot \uline{I}_0\\
- \Rightarrow\uline{I}_0&=\frac{\uline{U}_1}{1{,}15\,\mega\ohm}=\frac{1{,}5\,\volt}{1{,}15\,\mega\ohm}=1{,}3\,\micro\ampere\\
- \uline{U}_0&=\uline{Z}_{11}\cdot \uline{I}_0=100\,\kilo\ohm\cdot 1{,}3\,\micro\ampere=\uuline{130{,}4\,\milli\volt}
- \intertext{Nicht gefragt:}
- \uline{I}_2&=\frac{1}{R_2}\cdot (\uline{Z}_{11}-\uline{Z}_{21})\cdot \uline{I}_0=\frac{1}{600\,\ohm}\cdot 2{,}1\mega\ohm\cdot 1{,}3\,\micro\ampere=4{,}55\,\milli\ampere >> \uline{I}_0\\
- \text{Probe }\\
- %&=\frac{1}{R_1}\cdot (\uline{I}_2+\uline{I}_0)\cdot \uline{U}_0\\
- \uline{U}_1&=1{,}5\,\volt=R_1\cdot (\uline{I}_0+\uline{I}_2)+\uline{I}_0\cdot Z_{11}\\
- &=300\,\ohm\cdot (0{,}0013+4{,}55)\,\milli\ampere+1{,}3\,\micro\ampere\cdot 100\,\kilo\ohm=1{,}498\,\volt
- \end{align*}
- \clearpage
- \enlargethispage{1cm}
- Ist Ihnen aufgefallen, daß $\uline{Z}_{21}$ einen negativen Wert hat?\\[\baselineskip]
- Ein Widerstand nimmt elektrische Leistung auf, also ein Verbraucher.\\
- Dann muß also ein negativer Widerstand elektrische Leistung abgeben!
- Gibt es das in der Realität?\\[\baselineskip]
- Was steckt in dem Vierpol?\\[\baselineskip]
- Passiver Vierpol:\\
- Zum Beispiel mit 3 Widerständen in $T$ oder $\Pi$ Schaltung, ergibt jedoch keine Lösung!\\
- Aus der $\uline{Z}$ Matrix ist ersichtlich, daß $\uline{Z}_{21}=0$ und $\uline{Z}_{22}=0$ sind,
- somit existiert keine Kopplung vom Ausgang zum Eingang, sondern nur in Vorwärtsrichtung.\\[\baselineskip]
- Beispiel: Elektrodynamischer Lautsprecher der auf ein Kondensatormikrofon einwirkt. Kopplung nur vom Lautsprecher zum Mikrofon, nicht umgekehrt.\\[\baselineskip]
- Aktiver Vierpol: (Für Fortgeschrittene)\\
- Es muß sich um einen invertierenden Trennverstärker mit einem Eingangswiderstand von
- $100\,\kilo\ohm$ und einem Ausgangswiderstand von $2\,\mega\ohm$ handeln. Die Verstärkung ist zu berechnen.
- \begin{align*}
- \uline{U}_2&=\uline{U}_0-R_2\cdot \uline{I}_2=130{,}4\,\milli\volt-600\,\ohm\cdot 4{,}55\,\milli\ampere=-2{,}6\,\volt\\
- \uline{U}_q&=\uline{U}_2-\uline{Z}_{22}\cdot \uline{I}_2=-2{,}6\,\volt-2\,\mega\ohm\cdot 4{,}55\,\milli\ampere=-9102{,}6\,\volt\\
- V&=\frac{\uline{U}_q}{\uline{U}_0}=\frac{-9102{,}6\,\volt}{130{,}4\,\milli\volt}=-69805
- \end{align*}
- \begin{align*}
- \begin{tikzpicture}[scale=1.5]
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=1cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_1$};
- \draw [->,blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\tiny$R_1\cdot (\uline{I}_2+\uline{I}_0)$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=2cm,yshift=2cm]%Widerstand - nach EN 60617
- \draw (0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$R_2$};
- \draw [->,blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[below]{\footnotesize$R_2\cdot \uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick,black!25!, xshift=1.5cm, yshift=0cm]% Vierpol mit Innenleben
- \draw (0,-.2)rectangle(2.0,1.2);%node at(.75,.5)[right]{$(\uline{Z})$};
- \draw (0,0)--(-.5,0)(0,1)--(-.5,1)(2,0)--(2.5,0)(2,1)--(2.5,1);
- % \end{skope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm,rotate=90] %Z_11
- \draw [red!50!blue](0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667)
- [left] {$\uline{Z}_{11}$};
- \draw [<-,red!50!blue] (.3,-.2)--(.7,-.2)node at(.5,-.2)[right]{\footnotesize$\uline{Z}_{11}\cdot \uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=1cm]%Z_21
- \draw [red!50!blue](0,0)--(.3,0) (.3,-0.0667)rectangle(.7,0.0667) (.7,0)--(1,0)node at (.5,.0667) [above] {$\uline{Z}_{21}$};
- \draw [->,red!50!blue] (.3,-.2)--(.7,-.2)node at(.6,-.2)[below]{\footnotesize$-\uline{Z}_{21}\cdot \uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick,red!50!blue,xshift=1cm,yshift=0cm,rotate=90]%Spannungsquelle|
- \draw (0,0)--(1,0);%;node at(.5,-.133)[right]{$V\cdot \uline{U}_0$};
- \draw (.5,0)circle(.133);
- \draw [->] (.3,-.2)--(.7,-.2) node at (.3,-.2)[right]{\footnotesize$V\cdot \uline{U}_q$};
- \draw node at (.3,.025)[left]{\footnotesize$+$};
- \draw node at (.7,.025)[left]{\footnotesize$-$};
- \end{scope}
- \begin{scope}[>=latex,very thick,red!50!blue,xshift=0cm,yshift=0cm]%
- \draw (-.5,0)--(2.5,0)(-.5,1)--(0,1)(2,1)--(2.5,1);
- \end{scope}
- \end{scope} % Ende Vierpol Innenleben
- \begin{scope}[>=latex,very thick, xshift=0, yshift=0]
- \draw (0,0)--(1,0);
- \draw (1,1)--(1,2)--(2,2) (3,2)--(4,2)--(4,1);
- \draw (1,0)--(1,-.5)--(4,-.5)--(4,0);
- \fill (0,0)circle(.05) (0,1)circle(.05) (1,0)circle(.05) (1,1)circle(.05) (4,0)circle(.05) (4,1)circle(.05);
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=1cm]% Strompfeil
- \draw [->,red] (0,0)--(.4,0)node at(.2,0)[above]{\footnotesize$\uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=4cm,yshift=1cm]% Strompfeil
- \draw [->,red] (0,0)--(-.4,0)node at(-.2,0)[above]{\footnotesize$\uline{I}_2$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=-.2cm,yshift=1cm]% Strompfeil
- \draw [->,red] (0,0)--(.2,0)node at(.1,0)[above]{\footnotesize$\uline{I}_2+\uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=0cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(-.2,.5)[left]{\footnotesize$\uline{U}_1$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=1cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(0,.25)[left]{\tiny$\uline{U}_0=\uline{Z}_{11}\cdot \uline{I}_0$};
- \end{scope}
- \begin{scope}[>=latex,very thick,xshift=4cm,yshift=0cm]% Spannungspfeil
- \draw [->,blue] (0,.8)--(0,.2)node at(.2,.5)[right]{\footnotesize$\uline{U}_2=\uline{Z}_{21}\cdot \uline{I}_0$};
- \end{scope}
- \end{tikzpicture}
- \end{align*}
- \begin{minipage}[t]{1\textwidth}
- \centering
- \includegraphics[width =0.6\textwidth]{b16a8a}
- \end{minipage}
- \clearpage
- }{}%
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